hiren added a comment.
>>! In D1711#92, @rrs wrote:
> Hiren:
>
> There also should have been a printf before the panic string
> printf( "spin lock %p (%s) held by %p (tid %d) too long\n",
> m, m->lock_object.lo_name, td, td->td_tid);
>
> Can we see what that lovely printf has displayed?
Ah, my bad for not providing that earlier here:
spin lock 0xffffffff81364180 (callout) held by 0xfffff8000dc0e920 (tid
100111) too long
panic: spin lock held too long
Now,
(kgdb) print *(struct callout *)0xffffffff81364180
$8 = {c_links = {le = {le_next = 0xffffffff80d03d28, le_prev = 0xb0000}, sle
= {sle_next = 0xffffffff80d03d28}, tqe = {tqe_next = 0xffffffff80d03d28,
tqe_prev = 0xb0000}}, c_time = 0, c_precision = 4, c_arg = 0x0, c_func
= 0, c_lock = 0x0, c_flags = 0, c_cpu = 0}
if I print it's le_next, that node's le_prev is not pointing to
0xffffffff81364180
(kgdb) print *(struct callout *)0xffffffff80d03d28
$9 = {c_links = {le = {le_next = 0x74756f6c6c6163, le_prev =
0x6f207265626d754e}, sle = {sle_next = 0x74756f6c6c6163}, tqe = {tqe_next =
0x74756f6c6c6163,
tqe_prev = 0x6f207265626d754e}}, c_time = 7307497714779234406,
c_precision = 7809632219779637363, c_arg = 0x61206c656568776c, c_func =
0x20657a697320646e,
c_lock = 0x6f656d697420666f, c_flags = 690517109, c_cpu = 1701998624}
Also, trying to print le_next or le_prev is not working:
(kgdb) print *(struct callout *)0x6f207265626d754e
Cannot access memory at address 0x6f207265626d754e
(kgdb) print *(struct callout *)0x74756f6c6c6163
Cannot access memory at address 0x74756f6c6c6163
Is something wrong here or I am failing to understand this. (The latter has a
higher probability)
>
> In theory the lo_name should be "callout" and the %p should point to
> &cc_cpu[0].cc_lock
>
> Can we validate that these align correctly too?
How do I validate it?
REVISION DETAIL
https://reviews.freebsd.org/D1711
To: rrs, gnn, rwatson, lstewart, jhb, kostikbel, sbruno, imp, adrian, hselasky
Cc: julian, hiren, jhb, kostikbel, emaste, delphij, neel, erj, freebsd-net
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