flober# uname -a
FreeBSD flober 4.7-RELEASE FreeBSD 4.7-RELEASE #5:
Thu Dec 5 22:01:28 EET 2002
root@flober:/usr/obj/usr/src/sys/AKERNEL i386
I've got this question about flags C (RTF_CLONING)
and W (RTF_WASCLONED)(struct rtentry):
Let there are two active interfaces - fxp0
(ethernet) i lo0 (loopback):
flober# ifconfig
fxp0:
flags=8843<UP,BROADCAST,RUNNING,SIMPLEX,MULTICAST> mtu
1500
inet 192.168.1.1 netmask 0xffffff00 broadcast
192.168.1.255
ether 00:06:29:b0:df:65
media: Ethernet autoselect (none)
status: no carrier
lp0: flags=8810<POINTOPOINT,SIMPLEX,MULTICAST> mtu
1500
ppp0: flags=8010<POINTOPOINT,MULTICAST> mtu 1500
sl0: flags=c010<POINTOPOINT,LINK2,MULTICAST> mtu
552
faith0: flags=8002<BROADCAST,MULTICAST> mtu 1500
lo0: flags=8049<UP,LOOPBACK,RUNNING,MULTICAST> mtu
16384
inet 127.0.0.1 netmask 0xff000000
initial routing table :
flober# netstat -rn
Routing tables
Internet:
Destination Gateway Flags Refs
Use Netif Expire
127.0.0.1 127.0.0.1 UH 0
0 lo0
192.168.1 link#1 UC 0
0 fxp0
the flag C in the entry route to 192.168.1.0/24 means
that every time we use that entry (via
rtalloc/rtrequest/rtrequest_ign(/sys/net/route.c)) it
will be cloned (i.e. a new entry will be created
using the old a a template).Let's see:
for example:
flober# ping 192.168.1.1
...
flober# netstat -rn
Routing tables
Internet:
Destination Gateway Flags Refs
Use Netif Expire
127.0.0.1 127.0.0.1 UH 0
0 lo0
192.168.1 link#1 UC 1
0 fxp0
192.168.1.1 00:06:29:b0:df:65 UHLW 0
4 lo0
How fxp0 interface is changed to lo0? Where exactly in
the source (rtrequest)this is done?
Svetoslav Agafonkin
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