Just curious: I noticed that FreeBSD and NetBSD will give you a 50% longer listen queue than what was requested with the second argument of listen(2). (You get trunc(N*3/2)+1 for backlog=N). Thus with the default SOMAXCONN of 128 (this is settable with a sysctl) we actually have a listen queue of 193 connections. (OpenBSD dropped the "divide by two" and gives you 200% more than requested.) Obviously this doesn´t break anything - it has been this way at least since BSD 4.4 Lite - but it makes me curious. Does anybody know why this was implemented other than it is documented? Btw, Linux counts exactly (gives 2*N+1) but since 2.2 only completed connections are counted. TIA, Martin To Unsubscribe: send mail to [EMAIL PROTECTED] with "unsubscribe freebsd-net" in the body of the message