Re: BRIDGE breaks ARP? (more info)

[Rogier R. Mulhuijzen]

Not your culpa at all. It was my patch and I made a dumb mistake.

*tries to hide face in shame*

         DocWilco

At 12:07 5-2-01 -0800, you wrote:
>Ok, mea culpa
>
>I figured it out..
>Luigi.. does this fix it?
>
>
>         (void)memcpy(&itaddr, ea->arp_tpa, sizeof (itaddr));
>         TAILQ_FOREACH(ia, &in_ifaddrhead, ia_link) {
>#ifdef BRIDGE
>                 /*
>                  * For a bridge, we want to check the address irrespective
>                  * of the receive interface. (This will change slightly
>                  * when we have clusters of interfaces).
>                  */
>#define BRIDGE_TEST (do_bridge)
>#else
>#define BRIDGE_TEST 0 /* cc will optiise the test away */
>#endif
>                 if ((BRIDGE_TEST) || (ia->ia_ifp == &ac->ac_if)) {
>                         maybe_ia = ia;
>                         if ((itaddr.s_addr == ia->ia_addr.sin_addr.s_addr) ||
>                              (isaddr.s_addr == 
> ia->ia_addr.sin_addr.s_addr)) {
>                                 break;
>                         }
>                 }
>         }
>         if (maybe_ia == 0) {
>                 m_freem(m);
>                 return;
>         }
>         myaddr = ia ? ia->ia_addr.sin_addr : maybe_ia->ia_addr.sin_addr;
>         if (!bcmp((caddr_t)ea->arp_sha, (caddr_t)ac->ac_enaddr,
>             sizeof (ea->arp_sha))) {
>                 m_freem(m);     /* it's from me, ignore it. */
>                 return;
>         }
>
>
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