Alexander Leidinger wrote on 2016/12/19 20:54:
Quoting Miroslav Lachman <000.f...@quip.cz> (from Mon, 19 Dec 2016
18:57:39 +0100):

Alexander Leidinger wrote on 2016/12/19 17:56:

Quoting Miroslav Lachman <000.f...@quip.cz> (from Sun, 18 Dec 2016
13:20:31 +0100):

I don't expect it to be in the docs. I try to come up with something for
the man page for zfs (for the "attach to jail" part), but anyone shall
feel free to beat me with this.

Anyone with an idea where in the jail man page we should add something
too (I only had a look at the zfs man page when this issue came up)?

It would be nice to have this mentioned in zfs(8) man page (that user
in jail cannot manage jail's root dataset but can manage some
sub-dataset not required to boot the jail)

What about this? Better wording welcome.
---snip---
Index: zfs.8
===================================================================
--- zfs.8       (Revision 298108)
+++ zfs.8       (Arbeitskopie)
@@ -450,8 +450,11 @@
  dataset can be attached to a jail by using the
  .Qq Nm Cm jail
  subcommand. You cannot attach a dataset to one jail and the children
of the
-same dataset to another jails. To allow management of the dataset from
within
-a jail, the
+same dataset to another jails. You can also not attach the root file
system
+of the jail or any dataset which needs to be mounted before the zfs rc
script
+is run inside the jail, as it would be attached unmounted until it is
+mounted from the rc script inside the jail. To allow management of the
+dataset from within a jail, the
  .Sy jailed
  property has to be set and the jail needs access to the
  .Pa /dev/zfs
---snip---

And there can be some useful example in jail(8) man page in EXAMPLES.
There is section "Jails and File Systems" and there can be new section
"Manage ZFS from within jail" with basic notes about required jail
params, zfs set jailed property and example "hierarchy". (and warning
about gotchas with jailed=0 on jail's root directory)

Are you willing to come up with some text-only version/draft/outline for
this one?

I am not good at English but I will try something.

Thank you!

Miroslav Lachman


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