Ian,

It's not so much the induced latency, but the CPU usage.  Simply
invoking ipfw causes a noticeable amount of overhead, and with a
single rule it clocks in at 5% on the hardware in question.  This
ranks ipfw_chk in as the 2nd hungriest function, just below tcp_output
in the IRQ handler threads with a single rule.  With 3 rules, it
overtakes the top spot (each adding ~ .3% -.5%).

If there were an easy way to gain back that 5% on outbound traffic,
we'd gladly take it.  It sounds like being able to disconnect paths
from ipfw might be a science project for the future, though it does
seem it could garner some wider interest.

Jason

On Thu, Apr 16, 2015 at 12:12 AM, Ian Smith <smi...@nimnet.asn.au> wrote:
> On Thu, 16 Apr 2015 11:41:54 +0800, Julian Elischer wrote:
>  > On 4/15/15 5:09 AM, hiren panchasara wrote:
>  > > Apologies if this is something silly but I want to completely eliminate
>  > > ipfw from outgoing traffic perspective. I just want to have it on
>  > > incoming. I can always add "allow ip from any to any out" as the first
>  > > rule but that is still ipfw doing something.
>  > >
>  > > Is there a way to tell ipfw to not look at outbound traffic at all?
>  > no
>  > >
>  > > OR, the rule I mentioned is the best that can be done here?
>  > yes
>  >
>  > this touches on something I've been thinking of for a while.. per
>  > interface/direction rule sets.
>  > but that doesn't exist yet.
>  >
>  > you could write a kernel module that would disconnect the outgoing packet
>  > filter hooks
>  > but "hack" comes to mind as a description there.
>  >
>  > actually....  you could use the ipfw netgraph hook and only hook it up for
>  > incoming packets,
>  > but it would probably be not much more efficient than just having the rule,
>  > and more complicated to set up.
>
> I'm wondering if the cost of that one rule is even worth worrying about.
>
> Hiren, you might try running iperf (ono):
>
>  a) after 'ipfw disable firewall'
>
>  b) after just 'ipfw add 20000 allow ip from any to any'
>
>  c) after say 1000 rules before getting to (b) by such as:
>
>  for i in `jot - 0 999`; do
>         ipfw add $((i*10+1000)) count ip from any to any
>  done
>
> to then calculate a cost per rule.  Tens or hundreds of ns?
>
> Of course, whether that cost is significant depends on the sort of pps
> rates you're having (or hoping :) to deal with on the box in question ..
>
>  > > cheers,
>  > > Hiren
>  > >
>  > > ps: Please keep me cc'd as I am not subscribed.
>
> cheers, Ian
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