On Feb 10, 2010, at 10:42 AM, Dag-Erling Smørgrav wrote:
> Garrett Cooper <yanef...@gmail.com> writes:
>> Dag-Erling Smørgrav <d...@des.no> writes:
>>> A glob pattern can be trivially translated to a regular expression, but
>>> not the other way around. Basically, * in a glob pattern corresponds to
>>> [^/]*, ? corresponds to ., and [abcd] and [^abcd] have the same meaning
>> ^^^^ ???? ^^^^
>> The former is a positive assertion, where the latter is a negative
>> assertion -- how can they have the same meaning?
>
> Read the entire sentence. BTW, neither of these are assertions, and
> neither of these is negative in any sense, they are just different ways
> of selecting characters from the alphabet (in the extended sense).
Yes, I mentally omitted the second half because of the sentence construction.
Sorry ><.
>>> as in a regular expression. The glob pattern syntax has no equivalent
>>> for +, ?, {m,n}, (foo|bar), etc.
>>
>> +, {}, and () -- no... that's typically an extension to shell expanded
>> values (IIRC). ?
>
> I can't make sense of this - I'm not sure whether you misunderstood what
> I wrote, or just failed to express yourself clearly...
Ok -- redo: +, {} and () aren't typical shell glob operators. They're typically
extensions in certain shells (bash for instance).
>>> Finally, .* and .+ are *both* greedy. Perl's regular expression syntax
>>> includes non-greedy variants for both (.*? and .+? respectively).
>> Yes, but I didn't explicitly note those forms.
>
> No, but you claimed that .+ is not non-greedy, which is incorrect.
Yes. My previous understanding was incorrect. Thanks for the clarification :).
Cheers,
-Garrett_______________________________________________
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