Hello:
I have some weird behavior I'm trying to figure out and was wondering
if someone can point me in the right direction. I'm running a FreeBSD
6.1-RELEASE-amd64 machine. If I add /usr/lib32 to my LD_LIBRARY_PATH
it breaks all of my binaries on my 64-bit machine.
For example:
[EMAIL PROTECTED] ~]# file /bin/ls
/bin/ls: ELF 64-bit LSB executable, AMD x86-64, version 1 (FreeBSD),
dynamically linked (uses shared libs), stripped
[EMAIL PROTECTED] ~]# ldd /bin/ls
/bin/ls:
libutil.so.5 => /lib/libutil.so.5 (0x800630000)
libncurses.so.6 => /lib/libncurses.so.6 (0x80073d000)
libc.so.6 => /lib/libc.so.6 (0x800896000)
[EMAIL PROTECTED] ~]# ls -l /libexec/
total 306
-r-xr-xr-x 1 root wheel 163864 Aug 21 2007 ld-elf.so.1
-r-xr-xr-x 1 root wheel 146420 Aug 21 2007 ld-elf32.so.1
[EMAIL PROTECTED] ~]# export
LD_LIBRARY_PATH=$LD_LIBRARY_PATH:/usr/bin:/usr/lib:/usr/lib32:/usr/lib64
[EMAIL PROTECTED] ~]# ls
/libexec/ld-elf.so.1: /usr/lib32/libutil.so.5: unsupported file layout
[EMAIL PROTECTED] ~]# unset LD_LIBRARY_PATH
[EMAIL PROTECTED] ~]# ls
(normal ls output)
[EMAIL PROTECTED] ~]# ls -l /usr/lib/libut*
-r--r--r-- 1 root wheel 100518 Aug 21 2007 /usr/lib/libutil.a
lrwxrwxrwx 1 root wheel 17 Sep 11 11:44 /usr/lib/libutil.so ->
/lib/libutil.so.5
-r--r--r-- 1 root wheel 103846 Aug 21 2007 /usr/lib/libutil_p.a
[EMAIL PROTECTED] ~]# file /lib/libutil.so.5
/lib/libutil.so.5: ELF 64-bit LSB shared object, AMD x86-64, version 1
(FreeBSD), stripped
I would ASSUME that rtld would look at my LD_LIBRARY_PATH and use
/usr/lib to find libraries, not /usr/lib32. Why does it insist on
picking /usr/lib32 when "/bin/ls" is CLEARLY a 64-bit binary? This
doesn't make complete sense to me just yet.
Someone I'm sure is going "don't do that" and I agree. The issue is
I'm porting a library/framework (boost) and it creates a runtime
LD_LIBRARY_PATH for its gcc toolchain with the above which breaks the
build ROYALLY on FreeBSD 64-bit machine. I'm trying to come up with
the right heuristic here.
Any help would be much appreciated!
Thanks!
-aps
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