On Thu, 3 Jul 2008, Uladzislau Rezki wrote:
I've been writing a small kernel module, that provides information about
modification of the filesystem to user_land/userspace through the character
device. I'm using FreeBSD 4.10
So, my question is: Is there any way to get file name knowing its
descriptor?
Later versions of FreeBSD include a generic routine, vn_fullpath(9), to
convert a vnode reference into a pathname. It's not a particularly reliable
routine, in that it depends on the name cache, but it does work in most cases.
FreeBSD 4.x includes textvp_fullpath(9), which became the foundation for that
routine in later versions; it generates the path to the vnode used for the
text of a process, but could easily be generalized in much the same way
vn_fullpath(9) has been to return the pathname for arbitrary vnodes. Be aware
that pathnames are very much ephemeral in the UNIX design -- vnodes can and do
have one name, no names, or many names, and generating a name for an arbitrary
node wasn't part of the design requirements, so is quite difficult to do;
likewise, not all file systems use the name cache well or at all. If this is
just for debugging purposes, vn_fullpath(9) will do the trick, though, much of
the time.
Robert N M Watson
Computer Laboratory
University of Cambridge
static int
xxx_write (struct proc *p, struct write_args *uap)
{
struct vnode *vn;
struct file *file;
int sys_error;
/* do system call */
sys_error = write(p, uap);
if (sys_error != 0)
goto leave_call;
/* get the file */
file = curproc->p_fd->fd_ofiles[uap->fd];
/* get the vnode */
vn = (struct vnode *) file->f_data;
/* do we have a regular */
if (vn->v_type == VREG) {
...
...
...
}
As you can see we just know uap->fd.
Thanks.
--
Uladzislau Rezki
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