[EMAIL PROTECTED] (Dag-Erling Smørgrav) writes: > David Schultz <[EMAIL PROTECTED]> writes: > > When the line is there, the compiler is probably smart enough to > > realize that 'x=y; y=x' is (usually) a no-op, so it optimizes away > > both statements. > Wrong. The compiler is free to optimize away the second statement > provided that neither x nor y is declared volatile, but it cannot > optimize away the first statement.
I should add: unless it can determine with absolute certainty that x is not referenced later. DES -- Dag-Erling Smørgrav - [EMAIL PROTECTED] _______________________________________________ freebsd-hackers@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[EMAIL PROTECTED]"
