> > In <sys/proc.h>: > > /* > * pargs, used to hold a copy of the command line, if it had a sane > * length > */ > struct pargs { > u_int ar_ref; /* Reference count */ > u_int ar_length; /* Length */ > u_char ar_args[0]; /* Arguments */ > }; > > This does indeed seem to make little or no sense. Could someone explain > this? Is ar_args supposed to be a pointer or what?
This is a common technique for defining a structure which is some descriptive information about an array of objects is followed by an open-ended array of those objects. (In this case the "objects" are characters.) The ar_args member of the structure gives a name to that location in the structure without reserving any space (and thus when the technique is used, there can only ever be one [0] member and it must be at the end of the structure). You access the open-ended array of objects just as you would any other array embedded within a structure, E.G. instance->ar_args[n]. Not all compilers support defining zero-length arrays like this. And that's a pity; it's an incredibly useful technique, and the alternatives to it are not nearly as elegant and generally involve ugly recasting of pointers. -- Ian To Unsubscribe: send mail to [EMAIL PROTECTED] with "unsubscribe freebsd-hackers" in the body of the message