But what does this accomplish in the contect of release.8 if our purpose is
to 'copy' all the binaries to the new mfsroot?
On 18-Jul-01 Etienne de Bruin wrote:
> I was reading the Makefile in /usr/src/release and wondering about the
>
> for dir in bin sbin ; do \
> ln -sf /stand $$dir; \
> done
>
> part in release.8 - it is my understanding that all that is under /stand
is
> linked to files in $$dir.
>
> What does this accomplish?
No, it links $$dir to /stand. This creates /sbin and /bin directories so
that
you can still see /bin/ls even though ls is really in /stand/ls. This is to
make a "normal" path work right, and to allow scripts which assume the
default
location of utilities work.
--
John Baldwin <[EMAIL PROTECTED]> -- http://www.FreeBSD.org/~jhb/
PGP Key: http://www.baldwin.cx/~john/pgpkey.asc
"Power Users Use the Power to Serve!" - http://www.FreeBSD.org/
To Unsubscribe: send mail to [EMAIL PROTECTED]
with "unsubscribe freebsd-hackers" in the body of the message
