In message <[EMAIL PROTECTED]> Marc Tardif
writes:
: So why is %esp displaced by 16 bytes when only 8 bytes
: are necessary (4 for $0 and 4 for $.LC0)? And couldn't
: the compiler use a single instruction such as
: subl $16,%esp or addl $-16,%esp? Are two instructions
: used for pipelining purposes, where subl is synchro-
: nised with the first pushl and addl with the second
: pushl?
gcc tries to align stack to 16 byte boundaries as a speed
optiminzation. Why it doesn't do this in one instruction is beyond
me.
Warner
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