Steven, good day. Fri, Aug 05, 2011 at 12:02:19AM +0100, Steven Hartland wrote: > So I suspect that this is what's happening resulting in an extremely > small timeout instead of a large one. Now I know that passed in value > to the timeout is seconds * 1000 so we should be seeing 2148000 > for ccb->ccb_h.timeout now multiply that by 1000 (hz) and your over > the int wrap point 2147483647. > > So instead of the wrap point being 2147483 seconds (24 days), I suspect > because of the way this is structured its actually 2147 seconds (26mins). > > If this is the case the fix is likely to be something like:- > callout_reset(&slot->timeout, (int)(ccb->ccb_h.timeout * (hz / 2000)),
It will give you 0 timeout for all values of hz that are lower than 2000: hz is int, so you'll get integer division. Since ccb_h.timeout is u_int32_t, the proper way to handle this situation would be {{{ (u_int64_t)ccb->ccb_h.timeout * (u_int32_t)hz)/2000 }}} as long as the value of hz won't be greater than 2^32. Can you try the patch at http://codelabs.ru/fbsd/patches/ahci/AHCI-properly-convert-CAM-timeout-to-ticks.diff > What I don't understand is why the /2000 It gives (timeout_in_ticks)/2. The code in ahci_timeout does the following: {{{ /* Check if slot was not being executed last time we checked. */ if (slot->state < AHCI_SLOT_EXECUTING) { /* Check if slot started executing. */ sstatus = ATA_INL(ch->r_mem, AHCI_P_SACT); ccs = (ATA_INL(ch->r_mem, AHCI_P_CMD) & AHCI_P_CMD_CCS_MASK) >> AHCI_P_CMD_CCS_SHIFT; if ((sstatus & (1 << slot->slot)) != 0 || ccs == slot->slot || ch->fbs_enabled) slot->state = AHCI_SLOT_EXECUTING; callout_reset(&slot->timeout, (int)slot->ccb->ccb_h.timeout * hz / 2000, (timeout_t*)ahci_timeout, slot); return; } }}} So, my theory is that the first half of the timeout time is devoted to the transition from AHCI_SLOT_RUNNING -> AHCI_SLOT_EXECUTING and the second one is the transition from AHCI_SLOT_RUNNING -> TIMEOUT to give the whole process the duration of a full timeout. However, judging by the code, if the slot won't start executing at the first invocation of ahci_timeout that was spawned by the callout armed in ahci_execute_transaction, we can have timeouts more than for the specified amount of time. And if the slot will never start its execution, the callout will spin forever, unless I am missing something important here. May be Alexander can shed some light into this? -- Eygene Ryabinkin ,,,^..^,,, [ Life's unfair - but root password helps! | codelabs.ru ] [ 82FE 06BC D497 C0DE 49EC 4FF0 16AF 9EAE 8152 ECFB | freebsd.org ]
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