I don't know what you are doing with the 'gettext' in the call to 'printf'.
However for printf usage I would always limit the size of a string being
displayed with "%s", thus as "%-.80s" for instance.
I would *never* do:
printf ( argv [ 0 ] );
Since argv [ 0 ] indeed is untrusted.
However:
printf ( "%s", argv [ 0 ] );
already is a lot safer. You should not have to worry about any content of argv [
0 ] other than the length if that ever would be an issue. The content of argv [
0 ] in this case is not being parsed as a C-format string.
However for just displaying strings I would use puts or fputs. I mean why call a
heavy duty function as printf when the job can be very easily done with a
puts/fputs.
HTH
Jan
"John Doh!" wrote:
> >From: Alfred Perlstein <[EMAIL PROTECTED]>
> >To: John Doh! <[EMAIL PROTECTED]>
> >CC: [EMAIL PROTECTED], [EMAIL PROTECTED]
> >Subject: Re: How to stop problems from printf
> >Date: Thu, 7 Sep 2000 19:33:14 -0700
> >
> >* John Doh! <[EMAIL PROTECTED]> [000907 19:28] wrote:
> > > Hello to you am I C coder who to wish write programs we cannot exploit
> >via
> > > code such as below.
> > >
> > > >
> > > > main(int argc, char **argv)
> > > > {
> > > > if(argc > 1) {
> > > > printf(gettext("usage: %s filename\n"),argv[0]);
> > > > exit(0);
> > > > }
> > > > printf("normal execution proceeds...\n");
> > > > }
> > >
> > > Issue is must be getting format string from "untrusted" place, but want
> >to
> > > limit substitution of %... to the substitution of say in example the
> > > argv[0], but to not do others so that say given "usage: %s filename %p"
> >%p
> > > not interpret but to be print instead as literally so we get output of
> > > (saying to be argv[0] as test just for example) usage: test filename %p
> > >
> > > any hints you have I am very greatful for.
> >
> >try "%%p"
> >
> >-Alfred
> That is what I would do if I could always control string, but point is input
> string is not trusted...how to either validate or else to have printf limit
> to its arguments. Any ideas?
>
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--
Jan Knepper
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