Thus spake Poul-Henning Kamp ([EMAIL PROTECTED]):
> >between events. Because of this your T3 value can be considered the T1
> >value for the next random bit you generate.
> No it cannot. If you did that then the probability would skew from
> bit to bit. If the (t3-t2) was large bit N == 1 and the probability
> of bit N+1 == 0 is > .5 then.
Yes, but you can use the 3rd bit as bit 1 for the next step.
With 15 events, that gives 7 bits/second:
bit 1: 3 1 (is event 3 of the last bit)
bit 2: 2 1st
bit 3: 3 1
bit 4: 2 2nd
bit 5: 3 1
bit 6: 2 3rd
bit 7: 3 1
bit 8: 2 4th
bit 9: 3 1
bit 10: 2 5th
bit 11: 3 1
bit 12: 2 6th
bit 13: 3 1
bit 14: 2 7th
bit 15: 3 1 (is event 1 for the next bit)
Alex
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