On Mon, 2 Jul 2001 09:38:42 +0100
David Malone <[EMAIL PROTECTED]> wrote:
> On Sun, Jul 01, 2001 at 09:20:44PM -0700, Crist J. Clark wrote:
> > Hmmm... Looks like,
> >
> > # syslogd -a 192.168.1.0/29
> >
> > Will work and,
> >
> > # syslogd -a 192.168.1.1/29
> >
> > Won't.
>
> That's the standard behaviour of a netmask, isn't it? The usual
> way to check if host h is in network/netmask n/m is to check if:
>
> (h & m == n)
>
> this means that the bits of the network which are not in the mask
> must be zero.
>
> David.
>
Ok, changing the .1 to .0 worked for me. The last octect must be the network number.
Thanks
- David
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