Martok <list...@martoks-place.de> schrieb am Mo., 12. Aug. 2019, 10:18:
> Am 12.08.2019 um 09:40 schrieb Michael Van Canneyt: > > > > This question pops up from time to time since 15 years if not more. > > Fun fact: questions asking why this doesn't work have a higher Google > ranking > than the manual for "COPERATORS" ;-) > > @Ryan: as with all things FPC, ignore the manual, read the parser: > < > https://github.com/graemeg/freepascal/blob/4e6c609/compiler/pexpr.pas#L221 > > > > Turns out c-operators do not actually translate to their long form but > instead > have special, duplicated handling. Because of course they do. > The code you linked converts "a += b" to "tmp := @a; tmp^ := tmp^ + b", so except for using a temp to avoid duplicate calculation of "a" in how far is this not the long form? Regards, Sven >
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