On 06/13/2018 04:17 AM, Michael Schnell wrote:
On 12.06.2018 23:12, Klaus Hartnegg wrote:
No, it does not depend on the hardware, but on the setting of $N. Turbo Pascal
with $N+ rounds like FreePascal. But the default is $N-. In this mode Turbo
Pascal always rounds up.
What exactly does $N in Turbo pascal mean ? Obviously it in this case it (at
least for round() ) does not simply use the hardware for the calculation (as fpc
does).
$N switches between using "software code" OR using "a math coprocessor chip" for
real-type processing... transcribing the following while reading it off another
machine running TP6's Turbo CTRL-F1 screen... typos are mine...
{$N}
Numeric Processing Switch
=========================
Switches between the two different models of floating-point code generation
supported by Turbo Pascal
Syntax: {$N+} or {$N-}
Default: {$N-}
Type: Global
Menus: [X] 8087/80287
The {$N-} State
===============
In the {$N-} state, Turbo Pascal generates code to perform all real-type
calculations in software by calling run-time library routines.
The {$N+} State
===============
In the {$N+} state, Turbo Pascal generates code to perform all real-type
calculations using the 8087 numeric coprocessor.
* NOTE: You can also use the {$E+} directive to emulate the 8087. This gives you
access to the IEEE floating-point types without requiring that you install an
8087 chip.
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