On Tue, 26 Jul 2016, Santiago A. wrote:
El 26/07/2016 a las 12:27, Mattias Gaertner escribió:
a3:=a1+a2 => cp = 1252
a3:=a2+a1 => cp = 65001
Is that the expected behavior?
IMHO the result should be the same. And the only way is to make it
depend on a3, no matter what is in the left side. That's the way things
are done in Pascal
This is not correct. In pascal the right-hand side of an assignment has a well-defined type.
The compiler checks whether the type on the right is assignment-compatible to the left side.
Michael.
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