Anybody?
Is this designed? Or is this a bug? Shall I put it on Mantis?
On 26/01/2014 19:48, Martin Frb wrote:
TFoo1 is a sub range of FFoo
And it seems to match both TFoo and variant.
project1.lpr(24,3) Error: Can't determine which overloaded function
to call
project1.lpr(15,11) Hint: Found declaration: Bar(TFoo);
project1.lpr(11,11) Hint: Found declaration: Bar(Variant);
No other type seems to be bothered by variant.
Also variant is the only type, that I found that conflicts with TFoo1
Why?
I know I can declare
procedure Bar(a: TFoo1); overload;
and it will solve it (even if I leave all the others, because it is an
exact match).
But why does a subrange of integer/byte work? Subrange of integer does
not give the error, even so it could match both.
program Project1;
{$mode objfpc}
{// $mode delpti}
type
TFoo = (a1,a2,a3,a4,a5);
TFoo1 = a2..a4;
TFoo2 = 1..3;
TFoo3 = byte(1)..(3);
procedure Bar(a: Variant); overload;
begin end;
procedure Bar(a: Integer); overload;
begin end;
procedure Bar(a: TFoo); overload;
begin end;
var
f1: TFoo;
f2: TFoo1;
f3: TFoo2;
f4: TFoo3;
begin
Bar(f2);
end.
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