On Sat, 19 Mar 2011 08:30:45 +0100, Aleksa Todorovic
<alexi...@gmail.com> wrote:
>On Sat, Mar 19, 2011 at 06:07, Bo Berglund <bo.bergl...@gmail.com> wrote:
>>
>> 1) The second line in the loop contains the command std::max, how can
>> that be translated? I have not found any class definition for "std"
>> with a method "max"....
>>
>
>There is function Max in unit Math, so you could say:
>
>jBegin := Max(k-band, 1);
>
>> 2) The parameter into the function is a pointer *A of type double. To
>> me that indicates a value of some kind, but in the code it suddenly
>> seems to appear as an array with indexing. What would be the proper
>> pascal translation of this?
>
>Indeed. C doesn't actually have difference between pointer to some
>data and arrays. You could use open array:
>
>procedure Decompose(var A: array of double);
Thanks for the information!
Now I have found another very strange construct:
void ForwardModel::SetMixedBoundaryCondition(const int iElec,
const double* SX0,
const double* SY0,
const double* SZ0,
double* SX,
double* SY,
double* SZ)
Now it seems like the variable type declaration itself is a
pointer....
Instead of double *Name it is double* Name. What is the difference?
It is still being used as an array:
SX[n1] = SX0[n1] * (1.0 - w1);
Does C++ allow any placement of the * operator with the same meaning?
And what does const double* mean? Pointer to some object but not
allowed to change that object????
Having programmed Delphi for 16 years this is hard to wrap ones head
around. :-(
--
Bo Berglund
Developer in Sweden
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