On 30 Jan 11, at 22:28 , cobines wrote: > it is now a pointer to IBaseInterface, because of implicit QueryInterface? The reference changes because you have explicitly cast (the implementing object) to another interface.
> So, I think I can compare interface variables but first I have to > bring them to the same interface using "as", for example to IUnknown. Yes. This function will confirm the two provided interfaces are implemented by the same object... function EqIntf(a, b: IUnknown): Boolean; begin Result := (a as IUnknown) = (b as IUnknown); end; Regards Andrew.
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