Henry Vermaak <henry.verm...@gmail.com> > I can't understand what you are trying to say. An array is a pointer > to where the elements of the array resides in memory.
No, not in Pascal. In Pascal an array is a variable just like any other: A name for some memory area where values can be stored. > How else do you think it works? Just like "a : integer" -> reserve the needed number of bytes and let the programmer access the associated memory via the identifier "a". > Can you explain what would x[1] mean if it isn't dereferenced? Access the memory at address of "x + 1 * (size of element)". Just like you do array4 : record a1, a2, a3, a4 end; and access the record members respectively. It's a static address, known at compile time. No dereferencing. > No, it's not weakened by C-style all of a sudden, it's _always_ been > like this. No. Your confusing arrays and pointers. Or maybe, you're confusing Pascal and C. > As I've been trying to explain to you, there's no "obscure > compiler magic", if you put the brackets there, the compiler > dereferences. The dereferencing operator in Pascal is "^". Vinzent. -- GRATIS für alle GMX-Mitglieder: Die maxdome Movie-FLAT! Jetzt freischalten unter http://portal.gmx.net/de/go/maxdome01 _______________________________________________ fpc-pascal maillist - fpc-pascal@lists.freepascal.org http://lists.freepascal.org/mailman/listinfo/fpc-pascal
