Op maandag 23-06-2008 om 11:33 uur [tijdzone +0200], schreef Jonas
Maebe:
> On 23 Jun 2008, at 11:28, Joost van der Sluis wrote:
>
> > In the case of Firebird there are two possible names of the library,
> > and
> > both are tried. Can I safely add the {$linklib ...} statements for
> > both
> > libraries, even if one of them doesn't exist on the system?
>
> No. But you don't need {$linklib ...} statements in case you try to
> dynamically load libraries, only when they are linked to the program
> at compile time.
Ok.
I guess that:
const mysqllib='libmysqlclient.'+sharedsuffix;
{$linklib mysqllib}
doesn't work? (And I don't want it to link to 'mysqllib' ;) )
> > And will the unit be compilable at all if the library is not installed
> > on the system?
>
> Yes (linking happens when compiling a program or library that uses the
> unit, not when compiling the unit itself).
I meant a program that uses such a unit. But as long as it don's apply
to dynamically loaded libraries it's not a problem.
Joost.
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