I have written a program who's behavior depends on the name by which it has
been invoked.
This is not uncommon, for instance sendmail invoked as mailq behaves in a
completely
different way.
Anyway, it all works as intended as long as I *copy* the executable to a
different name.
However, if I use a symlink, the ParamStr(0) function doesn't work as I would
expect. It
always returns the name of the executable not the name of the link to it.
Example:
Program test;
Begin
WriteLn('This program was executed as: ',ParamStr(0));
end.
----
$ ./test
This program was executed as: /home/bob/pascal/test/test
cp test test1
./test1
This program was executed as: /home/bob/pascal/test/test1
$
$ ln -s test test1
$ ./test1
This program was executed as: /home/bob/pascal/test/test
$
-----
Is there a way to make this work properly? Another method? Is this a bug?
Bob
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