> On Jun 9, 2019, at 9:45 AM, Florian Klämpfl <[email protected]> wrote:
>
> And? It is obvious that FPC has to know what's the base type of a pointer
> else it couldn't do type checking.
I think all he means is this:
type
TInt = ^integer;
procedure DoThis(i: TInt);
begin
end;
var
a: ^integer;
begin
DoThis(a0);
He just wants function parameters to declare the new pointer type inline.
procedure DoThis(i: ^integer);
begin
end;
var
a: ^integer;
begin
DoThis(a0);
Regards,
Ryan Joseph
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