Julian wrote:
>Because it is an 8-bit D/A, the lowest level we can read is 2^8 lower than
>1024 = 1024/256 = 4mV. This is the value of one least significant bit
>(LSB). Also, let's assume that this is an optimally engineered 8-bit
>system. Because it is optimally engineered, let's say that the
>CCD/amplifier noise is a quarter of the LSB level i.e. 1mV RMS.
edited here
>Now, let's unplug the 8 bit D/A, and plug in a 12 bit D/A instead, to the
>same circuit. My point is - NOTHING CHANGES.
Won't the 12bit a/d converter allow the information between 4mv and the 1mv noise
level to be resolved?
Colin Maddock
