On Mon, May 20, 2019 at 14:40:24 +0200, Romane Lafon wrote: > + float tolerance = 1.0 - s->tolerance;
Strictly speaking 1.0f (or 1.f). > + float angle = cos(s->angle/180.0*PI); If you want a float as result, use cosf(s->angle / 180.f * M_PI). (I'm aware PI and M_PI aren't explicitly marked as float, but you can't have it all.) > + if (!s->is_mono && ((tolerance - fphase) < FLT_EPSILON)) { [...] > + if (s->is_mono && ((tolerance - fphase) < FLT_EPSILON) && > s->start_mono_presence) { [...] > + if (s->is_mono && ((tolerance - fphase) > FLT_EPSILON)) { [...] As tolerance and fphase are constant throughout this block of code, you could do this floating point comparison once, and reuse the boolean result. BTW, I reckon the third of those comparisons should be ">=", to properly complement the "<". > + if (!s->is_out_phase && (angle - fphase) > FLT_EPSILON) { [...] > + if (s->is_out_phase && ((angle - fphase) > FLT_EPSILON) && > s->start_out_phase_presence) { [...] > + if (s->is_out_phase && (angle - fphase) < FLT_EPSILON) { [...] Same here. > + float tolerance = 1.0 - s->tolerance; > + float angle = cos(s->angle/180.0*PI); Same as above. Cheers, Moritz _______________________________________________ ffmpeg-devel mailing list ffmpeg-devel@ffmpeg.org https://ffmpeg.org/mailman/listinfo/ffmpeg-devel To unsubscribe, visit link above, or email ffmpeg-devel-requ...@ffmpeg.org with subject "unsubscribe".