James Almer (2018-08-05): > This patch makes the code slightly less readable, IMO. What compiler > doesn't optimize out an integer division by 2 into a right shift?
Any compiler that cannot figure out that x is positive in this
convoluted loop. Signed divisions cannot be optimized as shifts. Make
everything unsigned and it will be fine.
But I do not understand the logic in having i going from 0 to w-1 just
to compute x from w-1 to 0.
unsigned w, x;
for (x = w - 1; x < w; x--)
would be better IMHO.
Regards,
--
Nicolas George
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