On Sun, Feb 14, 2016 at 10:06:16AM +0100, Paul B Mahol wrote:
> On 2/14/16, Timothy Gu <timothyg...@gmail.com> wrote:
> > +
> > +#include <string.h>
> > +#include "checkasm.h"
> > +#include "libavfilter/blend.h"
> > +#include "libavutil/common.h"
> > +#include "libavutil/internal.h"
> > +#include "libavutil/intreadwrite.h"
> > +
> > +#define WIDTH 256
> > +#define HEIGHT 256
> > +#define BUF_UNITS 9
> > +#define SIZE_PER_UNIT (WIDTH * HEIGHT)
> > +#define BUF_SIZE (BUF_UNITS * SIZE_PER_UNIT)
> > +
> > +#define randomize_buffers() \
> > + do { \
> > + int i, j; \
> > + for (i = 0; i < HEIGHT; i++) { \
> > + for (j = 0; j < WIDTH; j++) { \
> > + top1[i * WIDTH + j] = \
> > + top2[i * WIDTH + j] = i; \
> > + bot1[i * WIDTH + j] = \
> > + bot2[i * WIDTH + j] = j; \
>
> I think you failed to get my point.
>
> For 8bit blend if you blend 256x256 horizontal gradient
> with 256x256 vertical gradient you will get blend
> function response, which is unique. And covers all
> possibilities for 8bit formats.
You might have missed the fact that I changed WIDTH and HEIGHT as well, so
that for top it'll look like this
0 0 0 0 0 0 ... 0
1 1 1 1 1 1 ... 1
. . . . . . ... .
. . . . . . ... .
. . . . . . ... .
255 255 255 255 255 255 ... 255
For bottom it'll look like
0 1 2 3 4 5 ... 255
0 1 2 3 4 5 ... 255
. . . . . . ... .
. . . . . . ... .
. . . . . . ... .
0 1 2 3 4 5 ... 255
Or am I missing something?
Timothy
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