On Mon, Nov 30, 2015 at 10:52 PM, Nicolas George <geo...@nsup.org> wrote:
> Le decadi 10 frimaire, an CCXXIV, Muhammad Faiz a écrit :
>> - if (s->basefreq != BASEFREQ || s->endfreq != ENDFREQ) {
>> + if (s->basefreq != (double) BASEFREQ || s->endfreq != (double) ENDFREQ)
>> {
>
> Looks wrong to me. Since s->basefreq is double and operands are always
> converted to the largest type before comparison, the cast would be implicit.
> And BASEFREQ and ENDFREQ are double anyway.
>
> The problem, if any, is somewhere else.
>
double basefreq = BASEFREQ, endfreq = ENDFREQ;
if (basefreq == BASEFREQ && endfreq == ENDFREQ)
printf("equal\n");
else
printf("inequal\n");
I try with gcc -std=c89 / -std=c99 on mingw 32-bit
the result is inequal.
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