On Sat, Jun 10, 2023 at 10:55 PM Lynne <d...@lynne.ee> wrote:

> Why do they all have the same timing?
>

The processing procedure for these workloads is the same,
except for the difference in block width. (8xH, 4xH, 2xH)
So, the number of instructions remains constant.
Since these workloads handle a small amount of data each time,
the cycle count also stays the same.
However, if the quantity increases, instructions may involve more
micro-operations,
which affects the cycle count (workloads with larger block width may take
more cycles).
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