From: Rémi Denis-Courmont <r...@remlab.net>
There are no particular reasons to force the compiler to use the same
register as output and input operand. This forces an extra MOV
instruction if the input value needs to be reused after the swap.
In most cases, this makes no differences, as the compiler will seleect
the same register for both operands either way.
---
libavutil/arm/bswap.h | 17 ++++++++++-------
1 file changed, 10 insertions(+), 7 deletions(-)
diff --git a/libavutil/arm/bswap.h b/libavutil/arm/bswap.h
index 611ff0ad5b..c3460e035d 100644
--- a/libavutil/arm/bswap.h
+++ b/libavutil/arm/bswap.h
@@ -39,8 +39,10 @@ static av_always_inline av_const uint32_t
av_bswap32(uint32_t x)
#define av_bswap16 av_bswap16
static av_always_inline av_const unsigned av_bswap16(unsigned x)
{
- __asm__("rev16 %0, %0" : "+r"(x));
- return x;
+ unsigned y;
+
+ __asm__("rev16 %0, %1" : "=r"(y) : "r"(x));
+ return y;
}
#endif
@@ -48,17 +50,18 @@ static av_always_inline av_const unsigned
av_bswap16(unsigned x)
#define av_bswap32 av_bswap32
static av_always_inline av_const uint32_t av_bswap32(uint32_t x)
{
+ uint32_t y;
#if HAVE_ARMV6_INLINE
- __asm__("rev %0, %0" : "+r"(x));
+ __asm__("rev %0, %1" : "=r"(y) : "r"(x));
#else
uint32_t t;
- __asm__ ("eor %1, %0, %0, ror #16 \n\t"
+ __asm__ ("eor %1, %2, %2, ror #16 \n\t"
"bic %1, %1, #0xFF0000 \n\t"
- "mov %0, %0, ror #8 \n\t"
+ "mov %0, %2, ror #8 \n\t"
"eor %0, %0, %1, lsr #8 \n\t"
- : "+r"(x), "=&r"(t));
+ : "=r"(y), "=&r"(t) : "r"(x));
#endif /* HAVE_ARMV6_INLINE */
- return x;
+ return y;
}
#endif /* AV_GCC_VERSION_AT_MOST(4,4) */
--
2.37.2
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