Thank you for your comments! > > > + frame_data[channels * j] = 10000 * ((j / 10 * i) % 2); > > > + for (k = 1; k < channels; k++) > > > > > + frame_data[channels * j + k] = frame_data[channels * j] * 2; > > > > I do not understand the purpose of that "*2".
> i would guess, its intended to generate a signal thats different > for each of the 2 channels, Ludmila can probably confirm/or correct > if its not so > i dont see a problem here, its not the most variied test signal but > for now that should do. It can be chnaged later Yes, I want to generate different signal for different channels, my mistake to write "*2" instead of "*k". Kind regards, Ludmila Glinskih _______________________________________________ ffmpeg-devel mailing list ffmpeg-devel@ffmpeg.org http://ffmpeg.org/mailman/listinfo/ffmpeg-devel