Vicky, thanks for the idea.   I will see how it works for me.  I appreciate
the time/effort you put in to help me!

Greg


Greg Della-Croce
Skype: gdellacroce55
Cell: 407-408-2572
greg_della-cr...@sil.org
"If you assume you know the answer, you will miss having a breakthrough.
It’s okay to do what you did yesterday, but it will never be amazing again.".
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On Thu, Jan 26, 2017 at 11:13 AM, Vicky <jorwalvi...@gmail.com> wrote:

> Hi Greg,
>
> I have found a solution. Hope this helps!
>
>
> Function Contains(ChkFor As String, ChkRng As Range)
>
> For Each cell In ChkRng
>     If cell.Value = ChkFor Then
>         Contains = "Found"
>         Exit For
>     Else
>         Contains = "Not Found"
>     End If
>
> Next cell
> End Function
>
> The above code worked for me. :)
>
> Regards,
> Vicky
> On Thursday, January 19, 2017 at 7:15:03 PM UTC+5:30, Greg Della-Croce
> wrote:
>>
>> I am trying to create a very simple function that will take a string of
>> text and read a range of texts to see if I have any that string in any of
>> the ranges of the texts.   Should be a 10-minute problem to solve.   I am
>> however getting a #VALUE back.
>> I call the function with this:
>> =Contains(F2,' Scrape'!$D$2:$D$2062)
>>
>> The function is this:
>> Function Contains(ChkFor As String, ChkRng As Range) As String
>>
>> For Each cell In ChkRng
>>     If (InStr(cell.Value, ChkFor, 1)) Then
>>         Contains = "Found"
>>         Exit For
>>     End If
>>     Contains = "Not Found"
>> Next cell
>> End Function
>>
>>
>> OK, I said it was simple :)  However, can anyone point to the problem in
>> this code.   I have looked at it until I have become frustrated.
>>
>> Thanks,
>> Greg
>>
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