The INDEX() formula syntax is: INDEX(array, row_num, [column_num])
In your
formula:=C2-INDEX($E$2:$G$350,MATCH($A2,$E$2:$E$350,0),MATCH($B2,$F$2:$F$350,0))Your
second MATCH() function is comparing the value in column "B" (Size) tothe
values in column "F" and returns the row number as if it were a column number!
So, when looking for (7), it is found in the first row, so it returns a value
of (1)to the index() function.MATCH($A2,$E$2:$E$350,0) also returns row 1.so
your index() function looks like:INDEX($E$2:$G$350, row=1, column=1)which, when
looking for GM1-Black, returns "GM1-Black" instead of a number!
it's even more evident when you get to GM2-Blue in row 5 (4th row of
data)looking for (10) in column "F" returns row 4.INDEX($E$2:$G$350, row=4,
column=4)returns a #REF! error because columns E:G is only 3 columns. you
cannot return column 4.
I think the logic of this formula is flawed.you seem to want to subtract the
qty in "G" from the qty in "C" when A=E and B=FBut using
MATCH($B2,$F$2:$F$350,0) is going to get the FIRST occurrence when B=F,not the
one corresponding to when A=E.I think you're better off adding a "helper"
column and concatenate E and F like:=E2 & "_" & F2 (in column H)then use
:=C2-INDEX($E$2:$G$350,MATCH($A2&"_"&$B2,$H$2:$H$350,0),3)
or put =E2 & "_" & F2 in column D and use:=C2-VLOOKUP(A2&"_"&B2,D:G,4,FALSE)
Paul-----------------------------------------
“Do all the good you can,
By all the means you can,
In all the ways you can,
In all the places you can,
At all the times you can,
To all the people you can,
As long as ever you can.” - John Wesley
-----------------------------------------
On Tuesday, March 1, 2016 3:22 AM, Izhar <izharra...@gmail.com> wrote:
Please see the attachment, in the file I'm subtracting G2 from C2 with the
formula, can anyone tell me where I'm making a mistake
Thanks in advance
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