Hey Basole,
The code works perfectly fine with the small data sample I gave you.
However, after some further testing, I noticed that it does not work with
single digits that sometimes appear. Keep in mind that the single or double
digits may have a decimal and can be positive or negative.
A minor modification ?
Impressive.
Thanks.
On Wednesday, 18 December 2013 07:47:40 UTC-5, Basole wrote:
> 'Hi Bill, I redid the code, see if it works now:
>
>
> Sub SplitRange()
> Dim FirstPartM As String
> Dim SecontPartM As String
> Dim FirstPartH As String
> Dim SecontPartH As String
> Dim i As Long
> Dim Lastrow As Integer
> Lastrow = Cells.Find("*", [A1], , , xlByRows, xlPrevious).Row
> i = 1
> For i = i To Lastrow
> If InStr(Cells(i, 1), "+") > 0 Then
> FirstPartM = Left(Cells(i, 1), InStr(Cells(i, 1), "+") - 1)
> SecontPartM = Right(Cells(i, 1), Len(Cells(i, 1)) - InStr(Cells(i, 1),
> "+") + 1)
> Cells(i, 2) = FirstPartM
> Cells(i, 3) = SecontPartM
> Else
> If InStr(Cells(i, 1), "-") > 0 Then
> FirstPartH = Left(Cells(i, 1), InStr(Cells(i, 1), "-") - 1)
> SecontPartH = Right(Cells(i, 1), Len(Cells(i, 1)) - InStr(Cells(i, 1),
> "-") + 1)
> Cells(i, 2) = FirstPartH
> Cells(i, 3) = SecontPartH
> End If
> End If
> Next
> End Sub
> '_
> 'Basole.
>
>
> Em segunda-feira, 16 de dezembro de 2013 23h09min31s UTC-2, Bill Q
> escreveu:
>>
>> Hi,
>>
>> The macro below currently finds and removes selected characters that it
>> find. It works great. No issues.
>>
>> What I would like is this to be modified so that if it finds a character
>> within the array - it will move the character in question to the adjacent
>> cell to the right, THEN it will clear the character it just found.
>>
>> Thanks.
>>
>>
>> Sub CLEARNUMBERS001()
>> s = Array("+", "-", ".5", "-.5", "0", "1", "2", "3", "4", "5", "6", "7",
>> "8", "9")
>> For Each r In Selection
>> v = r.Value
>> For i = 0 To 13
>> v = Replace(v, s(i), " ")
>> Next
>> r.Value = v
>> Next
>> End Sub
>>
>
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