Hi Daniel

Thanks .... for solving my problem.

Nikhil Shah

On Tue, Jul 26, 2011 at 5:01 PM, Daniel <dcolarde...@free.fr> wrote:

> Hello,****
>
> ** **
>
> Have a look at the attached workbook.****
>
> ** **
>
> Regards.****
>
> ** **
>
> Daniel****
>
> ** **
>
> *De :* excel-macros@googlegroups.com [mailto:excel-macros@googlegroups.com]
> *De la part de* Nikhil Shah
> *Envoyé :* lundi 25 juillet 2011 20:58
> *À :* excel-macros@googlegroups.com
> *Cc :* Maries waran
> *Objet :* $$Excel-Macros$$ Date Formula****
>
> ** **
>
> Dear All Members
>
> Here I am posting my Question :
>
> ( 1 ). Starting Date : 25/08/2012 : Format will be dd/mm/yyyy
> ( 2 ). End Date : 05/05/2016 : Format will be dd/mm/yyyy
>
> Now I want Answer in the Following manner :
>
> ( 1 ) . 31/08/2012...
> ( 2 ).  30/09/2012
> ( 3 ).  31/10/2012
> ( 4 ).  30/11/2012
>
> Up to
>
> 05/05/2016 --- > End Date
>
> This means......
>
> I want the last date of each month from start Month to end Month and for
> this  the days should be calculated...accordingly
>
> The Months which have 31 days should be counted 31 and months which have 30
> days should be counted 30,if start month is incomplete the days should be
> calculated accordingly , For End Month the days should be counted up to the
> mentioned date.
>
> For Ex. : My Starting Dt.25/08 but August has 31 days So, I will count
> Difference Of  6 Days ( 31/08 - 25/08 )
>               My Ending Dt Will be 05/05/2016..So I will count only 5 days.
>
> I want Formula Only .... I Do Not Want VBA Code...And I am using Office
> Professional Edition 2003 Version...
>
> Thanks
>
> Nikhil Shah
>
>
>
>
> ****
>
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Some important links for excel users:
1. Follow us on TWITTER for tips tricks and links : 
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2. Join our LinkedIN group @ http://www.linkedin.com/groups?gid=1871310
3. Excel tutorials at http://www.excel-macros.blogspot.com
4. Learn VBA Macros at http://www.quickvba.blogspot.com
5. Excel Tips and Tricks at http://exceldailytip.blogspot.com
 
To post to this group, send email to excel-macros@googlegroups.com

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