Thanks!!!

On Wed, Jun 23, 2010 at 10:20 PM, Dave Bonallack
<davebonall...@hotmail.com> wrote:
> Hi Regina,
> The problem seems to be that XL has dropped off the leading zeros, so
> sometimes your data is 6 characters long, and sometimes just 5.
> When the data is 6 characters long, you need MID(E2,1,4)
> But when the data is only 5 characters long, you need MID(E2,1,3)
> (Since you aren't using 24 hour notation, you should never have the
> possibility of less than 5 characters.)
> Try using an "IF" statement to sort this out:
> IF(LEN(E2)=6,MID(E2,1,4),MID(E2,1,3))
> I notice that you have used ";" where I use "," which is a regional thing.
> You will have to change my formula accordingly.
> Regards - Dave.
>
>
>
>> Date: Tue, 22 Jun 2010 14:20:50 +0200
>> Subject: Re: $$Excel-Macros$$ Help
>> From: regina.medha...@gmail.com
>> To: excel-macros@googlegroups.com
>>
>> I am using the MID function for two columns which contains times and
>> moslty it works
>>
>> EgEg. the first column contains 111030, ie , 9 o'clock 10 minute and
>> 30 second , and the second column 112930 that is 11 o'clock 29 minute
>> and 30 second.
>>
>> I want to reduce the data and show only hour and minute so I used the
>> mid function MID(E2;1;4) so the first one will be 1103 and second
>> 1129. And I subtract the second from the first and got 26 minute.
>>
>> But in some rows the first column contains 91030, ie , 9 o'clock 10
>> minute and 30 second , and the second column 112930 that is 11
>> o'clock 29 minute and 30 second and the first one will be 9103 and
>> second 1129. but the result will be wrong.
>>
>> Do any one knows an alternative function in excel whick can work for
>> this purpose.
>>
>> Thanks for your help in advance.
>>
>> Regina
>>
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