Hi Ramesh,
Supposing that no other split-sequences occur than space, underscore
or hyphen (or a combination of these), then following routine should
do the job...
Enjoy and let me know if it did help you out.
Kind regards
Paul Willekens
'=======================================================================
Sub ExtractNumber()
Dim cChar
Dim cNumber
Dim lDone
Dim lFount
Dim nLen
Dim nPos
Dim nRow
Dim nStart
nRow = 2
lDone = False
While lDone = False
cContent = Cells(nRow, 1)
nLen = Len(cContent)
cNumber = ""
If nLen < 1 Then
lDone = True
Else
For nPos = 1 To nLen
cChar = Mid(cContent, nPos, 1)
If IsNumeric(cChar) Then
If IsNumeric(Mid(cContent, (nPos + 1), 1)) Then
'this must be the number
lFound = False 'will be set True when the split-factor is
found
nStart = InStrRev(Left(cContent, nPos), " ") + 1
While nStart <= nLen
If Not lFound Then
cChar = Mid(cContent, nStart, 1)
If cChar = " " Or cChar = "_" Or cChar = "-" Then
cNumber = cNumber & "-"
lFound = True
cChar = Mid(cContent, (nStart + 1), 1)
If cChar = " " Or cChar = "_" Or cChar = "-" Then
nStart = nStart + 1
If Mid(cContent, (nStart + 1), 1) = " " Then
nStart = nStart + 1
End If
End If
Else
cNumber = cNumber & Mid(cContent, nStart, 1)
End If
nStart = nStart + 1
Else 'last part
nPos = InStr(nStart, cContent, " ")
If nPos = 0 Then
nPos = nLen
Else
nPos = nPos - 1
End If
cNumber = cNumber & Mid(cContent, nStart, (nPos - nStart
+ 1))
nStart = nLen + 1
End If
Wend
nPos = nLen
End If
End If
Next
If Not cNumber = "" Then
Cells(nRow, 2).Value = cNumber
End If
End If
nRow = nRow + 1
Wend
End Sub
'=======================================================================
--
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