Hi Mr.Andy
I appreciate your patience to explain in such a great depth of how to solve
this problem. Fortunately i am using Office 2007 and the problem got solved
in seconds....

I guess u have proficient knowledge about Excel formulas, Thanks to this
group.

Thank you very very very much
Satish

On Mon, Mar 30, 2009 at 3:06 PM, Aindril De <aind...@gmail.com> wrote:

> Hi Satish,
>
> If you are using office 2007 then you can easily use the COUNTIFS function:
> =COUNTIFS(A1:A23,"a",B1:B23,"c") will check how many "c" are there
> corresponding to "a", same thing can be done for "b" as well.
>
> However if you are using Office 2003 or any lower version, then you have no
> option other than using the *SUMPRODUCT* function as the *COUNTIF *function 
> does
> not support multiple criteria:
> =SUMPRODUCT(((A1:A23)="a")*((B1:B23)="c")*1) will check how many "c" are
> there corresponding to "a", same thing can be done for "b" as well.
>
> Hope it helps.
>
> Regards,
> Andy
>
> On Mon, Mar 30, 2009 at 2:13 PM, satish <satishpag...@gmail.com> wrote:
>
>>
>> Hello group member
>>
>> I need an help with respect to "Count-if Function". this is what my
>> query is
>>
>> say in "column A" there are many number of A, B, C (no any sequence)
>> etc in 1000 rows (one letter in each cell)
>>
>> Next, in "Column B" there are again many no. of A, B, C etc...
>>
>> I wanna know how many B's are there in "Column B" corresponding to A
>> in "column A" like wise how many C's in column B corresponding to A in
>> "column A" etc.. i should be able to find any kind of combination...
>>
>> If any one thinks they know the answer, Please share with this group.
>>
>> Regards
>> Satish
>>
>>
>>
>>
>
> >
>

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