Why this has to continue ? What a waste of energy for a result well known,
it will loop back again, trolls not only destroy a good mailing list, they
destroy earth by wasting energy for useless childish problems resolved 120
years ago.

Le dim. 26 janv. 2025, 20:38, Jesse Mazer <[email protected]> a écrit :

>
>
> On Sun, Jan 26, 2025 at 12:26 PM Alan Grayson <[email protected]>
> wrote:
>
>>
>>
>> On Sunday, January 26, 2025 at 10:04:54 AM UTC-7 Alan Grayson wrote:
>>
>> On Sunday, January 26, 2025 at 9:13:54 AM UTC-7 Jesse Mazer wrote:
>>
>> On Sun, Jan 26, 2025 at 1:54 AM Alan Grayson <[email protected]> wrote:
>>
>> On Saturday, January 25, 2025 at 11:25:53 PM UTC-7 Brent Meeker wrote:
>>
>> On 1/25/2025 10:13 PM, Alan Grayson wrote:
>>
>>     On Saturday, January 25, 2025 at 9:06:18 PM UTC-7 Brent Meeker wrote:
>>
>> On 1/25/2025 6:34 PM, Alan Grayson wrote:
>>
>>    On Saturday, January 25, 2025 at 6:47:22 PM UTC-7 Jesse Mazer wrote:
>>
>>        On Sat, Jan 25, 2025 at 8:07 PM Alan Grayson <[email protected]>
>> wrote:
>>
>>             On Monday, December 9, 2024 at 2:01:28 PM UTC-7 Brent Meeker
>> wrote:
>>
>> >
>> > Nothing odd about dilation and contraction when you know its cause.
>> > But what is odd is the fact that each frame sees the result
>> > differently -- that the car fits in one frame, but not in the other --
>> > and you see nothing odd about that, that there's no objective reality
>> > despite the symmetry. AG
>>
>> The facts are events in spacetime.  There's an event F at which the
>> front of the car is even with the exit of the garage and there's an
>> event R at which the rear of the car is even with the entrance to the
>> garage.  If R is before F we say the car fitted in the garage. If R is
>> after F we say the car did not fit.  But if F and  R are spacelike, then
>> there is no fact of the matter about their time order.  The time order
>> will depend on the state of motion.
>>
>> Brent
>>
>> Jesse; it's the last two of Brent's sentences that I find ambiguous. What
>> does he mean?
>>
>> What about them do you find ambiguous?
>>
>> He's just saying that if there's a spacelike separation between the
>> events F and R (as there was in his numerical example), then you can find a
>> frame where R happens after F (as is true in the car frame where the car
>> doesn't fit), and another frame where F happens after R (as is true in the
>> garage frame where the car does fit).
>>
>> *What does he mean by "But if F and  R are spacelike, then there is no
>> fact of the matter about their time order."? (What you wrote above?) *
>>
>> Brent writes > Yes.  Just what Jesse wrote above.  It means the two
>> events were so close together in time and distant in space that something
>> would have to travel faster than light to be at both of them.
>>
>> *More important I just realized that in the frame of car fitting, the
>> events F and R aren't simultaneous, so how does one apply disagreement on
>> simultaneity when one starts with two events which are NOT simultaneous? AG*
>>
>> Brent writes > That's why you should talk about events being
>> spacelike...the relativistic analogue of simultaneous.
>>
>> *I'd like to do that. BUT if the Parking Paradox is allegedly solved by
>> star**ting in the garage frame where the car fits, the pair of events
>> which define fitting are not spacelike since they occur at different
>> times! *
>>
>> You didn't read the definition of "spacelike" that I wrote above.  You
>> want everything fed to you in tiny bites of knowledge which you forget
>> eight lines later, so the questions start all over again.
>>
>> Brent
>>
>>
>> *I read it, but didn't like it. Big difference. Maybe you should stop
>> trying to read my intentions. You may be smart, but reading my intentions
>> is way above your pay grade. How could two events with the same time
>> coordinate be referred as "so close together". Moreover, in all discussions
>> of solutions to the paradox, events that are simultaneous in one frame, are
>> shown not simultaneous in another frame. This being the case, the two
>> events of the car fitting in garage frame are simply NOT simultaneous!
>> Also, Jesse seems to be referring to different events than the ones you
>> refer to. So there's a muddle IMO. As a teacher, your preferred method is
>> to intimidate students. Grade now D+. AG *
>>
>>
>> Why do you think I am referring to different events? I referred to the
>> same events F and R that Brent did (F is the event of the front of the car
>> coinciding with the garage exit, R is the event of the rear of the car
>> coinciding with the garage entrance).
>>
>> If you don't like Brent's verbal explanation, I also gave you a
>> mathematical definition of "spacelike separation" in two recent posts on
>> the "Brent on Parking Paradox" thread at
>> https://groups.google.com/g/everything-list/c/QgVdhXi3Hdc/m/KC2lIKyrDQAJ
>> and
>> https://groups.google.com/g/everything-list/c/QgVdhXi3Hdc/m/FF7TpbG-DQAJ
>> -- "If you know the distance x and time interval t between the two
>> points/events in the coordinates of any inertial frame, to say they are
>> spacelike separated just means that x > ct (and an equivalent definition is
>> that neither point is in the past or future light cone of the other one)".
>> Since I explicitly referred to a time interval t between the two events, if
>> you had paid attention to that you would have known not to say "the pair of
>> events which define fitting are not spacelike since they occur at different
>> times".
>>
>> Jesse
>>
>>
>> *Earlier I confused spacelike with timelike, but now I am clear about
>> that. I also recall your post defining spacelike for simultaneous events. I
>> was confused about my reference to different events referred to by you and
>> Brent. The core issue now is that we need simultaneous events in the garage
>> frame where the car fits, to determine a disagreement about simultaneity
>> with the car frame. Otherwise, it make no sense to speak of any
>> disagreement about simultaneity.*
>>
>>
> I think it does make sense to say that disagreement about order of
> non-simultaneous events is a consequence of the relativity of simultaneity,
> I explained why in the recent post at
> https://groups.google.com/g/everything-list/c/gbOE5B-7a6g/m/zx1LFvELDgAJ
> -- did you read it? And it is common to include disagreement about event
> order in discussions of the relativity of simultaneity, as in the the
> second paragraph of the "description" section of the relativity of
> simultaneity wiki article at
> https://en.wikipedia.org/wiki/Relativity_of_simultaneity#Description
>
> Anyway, this is just a linguistic issue, if you want to use a separate
> phrase "relativity of event-order" you can, it only leads to a cosmetic
> change to the argument--instead of saying that disagreement about fitting
> is a consequence of relativity of simultaneity, one can just say
> disagreement about fitting is a consequence of relativity of event-order
> for the events F and R. On the other hand, if you want to think about
> fitting not in terms of events F and R but just in terms of a comparison of
> the length of the garage with the length of the car, then since "length" in
> a given is always defined in terms of the distance between front and back
> at a single moment in time in that frame, that does involve picking events
> on worldlines of the front and back that are simultaneous, so the fact that
> the two frames disagree on the lengths can be understood in terms of their
> disagreement about simultaneity.
>
>
>>
>> *I suppose, from you pov, I did it again; referring to difference in
>> times for fitting to mean non-simultaneous. Did Brent ever prove the events
>> could be non-simultaneous in time, yet be spacelike? I don't think so. AG *
>>
>
> Yes, Brent's definition of spacelike separation at
> https://groups.google.com/g/everything-list/c/gbOE5B-7a6g/m/CgV9j1QQDgAJ
> was "the two events were so close together in time and distant in space
> that something would have to travel faster than light to be at both of
> them", which is equivalent to my definition that x > ct. For example if an
> event A happens on Earth today, and 2 years later another event B happens
> on Alpha Centauri 4 light years away (measured in the Earth/Alpha Centauri
> rest frame), something would have to travel twice the speed of light to be
> at both of them, and x > ct because x = 4 light years and ct = 2 light
> years. On the other hand if event B happened on Alpha Centauri 8 years
> after A, the two events would be timelike separated (x < ct) and something
> traveling at half the speed of light could be at both. And if event B
> happened on Alpha Centauri 4 years after A, the two events would be
> lightlike separated (x = ct) and something would need to travel at exactly
> the speed of light to be at both events.
>
> Jesse
>
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