On 12/17/2024 11:21 PM, Alan Grayson wrote:
On Tuesday, December 17, 2024 at 10:16:51 PM UTC-7 Brent Meeker wrote:
On 12/17/2024 7:52 PM, Alan Grayson wrote:
On Tuesday, December 17, 2024 at 6:57:28 PM UTC-7 Alan
Grayson wrote:
On Tuesday, December 17, 2024 at 2:33:46 PM UTC-7
Brent Meeker wrote:
On 12/17/2024 9:25 AM, Alan Grayson wrote:
Yes, you look at it just in terms of lengths, which is
what I did in the
first pair of diagrams. But the relativity of
simultaneity is another
way to look at the same problem, which is what I showed
in my last posting.
*Another way, but not the only way. AG *
We seem to be on the same page concerning use of length
contraction to explain the
differing results in the frames under consideration. But I remain
unclear how the
disagreement of simultaneity can also give the same results. For
example, suppose
from the pov of the garage frame, the car fits in the garage for
sufficient v, with room
to spare, but the front and rear end EVENTS do not Lorentz
transform into simultaneous
events in the car frame. Can't there be other ways for the car to
fit, using another set
of events which*are* simultaneous in the car frame? AG
Sure. If the car's speed was just right, it would be the same
length as the garage. Then in the diagram A and B would be at the
same time in the garage frame the car would be just the right
length such that the rear of the car entered the garage just as
the front exited the garage. Since we know the car is 12 long and
the garage is 10 long we can calculate the required speed from
10/12 =sqrt{1-v^2} which yields v=0.553 if I did the arithmetic right.
That would be 0.553c. So, if the front and back events in the garage
frame are simultaneous in the car frame AND in the garage frame,
Nobody said that the events were simultaneous in the car frame. The car
is contracted in the car frame. You keep throwing shit in problem just
to keep it going. I'm starting to suspect you're just a troll.
Brent
why is it claimed that the solution to the problem, whatever it is,
depends on disagreements of simultaneous events, when there are none?
And if we get different results for fitting in the garage, where, for
example, the car never fits, is there anything about this result that
implies something contradictory or paradoxical? AG
Brent
--
You received this message because you are subscribed to the Google
Groups "Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send
an email to [email protected].
To view this discussion visit
https://groups.google.com/d/msgid/everything-list/bb3a9717-5983-46e4-9842-8d4c5bcae35en%40googlegroups.com
<https://groups.google.com/d/msgid/everything-list/bb3a9717-5983-46e4-9842-8d4c5bcae35en%40googlegroups.com?utm_medium=email&utm_source=footer>.
--
You received this message because you are subscribed to the Google Groups
"Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To view this discussion visit
https://groups.google.com/d/msgid/everything-list/7395d5f8-7cdf-4bbf-a7b6-e7b4c43c58e4%40gmail.com.
