Re: [O] Insert a line separator in table results

[Arun Persaud]

This works for me.

#+BEGIN_SRC python
    x = [["label 1", "label 2", "label 3"]]
    x.append(None)
    x.append((4, 5, 6))
    x.append((7, 8, 9))
    return (x)
#+END_SRC

#+RESULTS:
| label 1 | label 2 | label 3 |
|---------+---------+---------|
|       4 |       5 |       6 |
|       7 |       8 |       9 |

Arun