"Sebastien Vauban" <sva-n...@mygooglest.com> writes:
> Hello,
>
> I'm trying to generate R graphs from lines found in the *Messages* buffer with
> the following code of mine:
>
> #+begin_src emacs-lisp :results output table
> (setq txt nil)
> (with-current-buffer "*Messages*"
> (goto-char (point-min))
> (while (re-search-forward
> "^Retrieving newsgroup: \\(.+\\)"
> nil t)
> (setq txt (concat txt (format "%s" (match-string 1)) "\n"))
> (princ txt)))
> #+end_src
>
> However, the results is always an example block, NEVER in an Org _table_ --
> and
> I don't understand why. Does anybody?
>
> Best regards,
> Seb
I bet because ":results output" in Emacs Lisp is only interpreted as a
string. You're better off just returning a list with something like the
following.
#+begin_src emacs-lisp :results output table
(let (txts)
(with-current-buffer "*Messages*"
(goto-char (point-min))
(while (re-search-forward
"^Retrieving newsgroup: \\(.+\\)"
nil t)
(push (match-string 1) txts)))
txts)
#+end_src
--
Eric Schulte
https://cs.unm.edu/~eschulte
PGP: 0x614CA05D
