I find a logical error in an if statement '(X & 0xfc) == 0x3' is always false
After pointing this out, Larry Finger informed what would be the correct one.
'(X & 0x3) == 0x3'
Signed-off-by: Rickard Strandqvist <rickard_strandqv...@spectrumdigital.se>
---
drivers/staging/rtl8821ae/rtl8821ae/hw.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/drivers/staging/rtl8821ae/rtl8821ae/hw.c
b/drivers/staging/rtl8821ae/rtl8821ae/hw.c
index 1b8583b..52322e3 100644
--- a/drivers/staging/rtl8821ae/rtl8821ae/hw.c
+++ b/drivers/staging/rtl8821ae/rtl8821ae/hw.c
@@ -1623,7 +1623,7 @@ static int _rtl8821ae_set_media_status(struct
ieee80211_hw *hw,
rtl_write_byte(rtlpriv, (MSR), bt_msr);
rtlpriv->cfg->ops->led_control(hw, ledaction);
- if ((bt_msr & ~0xfc) == MSR_AP)
+ if ((bt_msr & MSR_AP) == MSR_AP)
rtl_write_byte(rtlpriv, REG_BCNTCFG + 1, 0x00);
else
rtl_write_byte(rtlpriv, REG_BCNTCFG + 1, 0x66);
--
1.7.10.4
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