On Wed, Jun 22, 2016 at 11:15:44AM +0200, Edward Bartolo wrote: > Hi, > > Now I have several exercises from "The C programming language" > (Kernighan & Ritchie). Some question look rather challenging... > > I learnt arrays are always passed by reference to function calls. So, > I wrote the following program to make use of this so that a variable > in main() is modified in a function call.
We have already debated this point, but gain, this is a misconcenption that you have to abandon, because it's *wrong*. There is no "passing by reference" in C. Forget it. No references. Only *values*. Everything is passed *by* *value* in C. You will never pass "an array" to a function call in C. You will instead pass the *value* of a *pointer* to a contiguous region of RAM which contains the elements of your array. You pass *an adress*, namely the address of the first position in RAM where your array stays, not "the array", or a reference to the array. And this is implemented by copying on the stack the *value* of the pointer (i.e., the address), so that your function can access the array that start at that address. You *never* pass anything by reference in C. Never ever. C has only pass-by-value. HND KatolaZ -- [ ~.,_ Enzo Nicosia aka KatolaZ - GLUGCT -- Freaknet Medialab ] [ "+. katolaz [at] freaknet.org --- katolaz [at] yahoo.it ] [ @) http://kalos.mine.nu --- Devuan GNU + Linux User ] [ @@) http://maths.qmul.ac.uk/~vnicosia -- GPG: 0B5F062F ] [ (@@@) Twitter: @KatolaZ - skype: katolaz -- github: KatolaZ ] _______________________________________________ Dng mailing list Dng@lists.dyne.org https://mailinglists.dyne.org/cgi-bin/mailman/listinfo/dng
