This is correct: int **L ===> Address1(preallocated) -----> Address2(not allocated) -----> > int (not allocated) >
When you declare a variable, the compiler will reserve memory space to store it. No matter how may asterisks a variable has, from the compiler's view it's only a memory address. So it will reserve space to store an address: int *****x; x will store a memory address, so the compiler has to reserve 8 bytes (amd64) for it. Conclusion: the size of a pointer will be always the same, no matter what is pointing to (an integer, a char, an address...) On Tue, Mar 29, 2016 at 9:00 AM, Edward Bartolo <edb...@gmail.com> wrote: > Hi, > > As far as I know, the compiler automatically allocates memory for the > address where a pointer is saved. The unallocated part is the data > attached to a pointer. What happens with a pointer to a pointer like > void**? Does the compiler allocate memory for two addresses with the > first one in the chain pointing to the second one? Does it allocate > memory only for the first address? > > What I can say about pointers: > > a) int * K ===> Address(preallocated) -------------------> integer > [ not preallocated ] > > b) void** V ===> Address1 (preallocated) ------> Address2(preallocated) > > OR: > > void** V ===> Address1 (preallocated) -----> Address2(not preallocated) > > ? > > c) int **L ===> Address1 (preallocated) -----> Address2(allocated) > -----> int (not allocated) > > OR > > int **L ===> Address1(preallocated) -----> Address2(not allocated) > -----> int (not allocated) > > By 'preallocated' I mean the compiler will automatically generate code > to allocate memory for the actual pointer not the data. > > d) Is this allowed: void***, int***, double***, etc? > _______________________________________________ > Dng mailing list > Dng@lists.dyne.org > https://mailinglists.dyne.org/cgi-bin/mailman/listinfo/dng >
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