Maybe...
Here you are the same program written in both languages:
CASE 1 (C Language):
# include <stdio.h>
void func(int*);
int main(void)
{
int i=1;
func(&i);
printf( "%d", i);
return 0;
}
void func(int *x)
{
*x = 2;
}
CASE 2 (C++ Language):
#include <iostream>
void func(int &);
int main()
{
int n = 1;
func(n);
std::cout << n;
return 0;
}
void func(int &x)
{
x = 2;
}
/ **** END **** /
CASE 1: The argument is not a reference, it's an address.
CASE 2: The argument is a reference
I have several books about C/C++ language (by G. Leblanc, Fco. Charte,
Javier Ceballos, etc...)
H. Schildt is the only one using this terminology in C.
Cheers,
Aitor.
On 12/11/2015 10:04 AM, Irrwahn <irrw...@freenet.de> wrote:
Ceterum censeo: There is no pass by reference in C,
has never been, and will presumably never be. Heck,
the C standard doesn't mention the concept at all,
not even in a non-normative foot note!
HTH, HAND
Irrwahn
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